COMEDK · Physics · 6. Work Power Energy
A body of mass 0.5 kg is dropped from a height of 2 m on the top of the spring of length 0.6 m , fixed vertically on the horizontal table. If the spring is depressed by a distance of 10 cm , then what will be the spring constant of the spring? \(g=10 \mathrm{~ms}^{-2}\)
- A \(200 \mathrm{Nm}^{-1}\)
- B \(150 \mathrm{Nm}^{-1}\)
- C \(1500 \mathrm{Nm}^{-1}\)
- D \(2000 \mathrm{Nm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(1500 \mathrm{Nm}^{-1}\)
Step-by-step Solution
Detailed explanation
Total height fallen: \(h = (2 - 0.6) + 0.1 = 1.5\) m By energy conservation: \(mgh = \dfrac{1}{2}kx^2\) \(0.5 \times 10 \times 1.5 = \dfrac{1}{2} \times k \times (0.1)^2\) \(7.5 = 0.005k\) \(k = 1500 \ Nm^{-1}\)
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