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COMEDK · Physics · 3. Motion In One Dimension

A body is projected vertically upwards. The times corresponding to height \(h\), while ascending and descending are \(t_{1}\) and \(t_{2}\), respectively. Then, the velocity of projection is ( \(g\) is acceleration due to gravity)

  1. A \(g \sqrt{t_{1} t_{2}}\)
  2. B \(\frac{g t_{1} t_{2}}{t_{1}+t_{2}}\)
  3. C \(\frac{g \sqrt{t_{1} t_{2}}}{2}\)
  4. D \(\frac{g\left(t_{1}+t_{2}\right)}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{g\left(t_{1}+t_{2}\right)}{2}\)

Step-by-step Solution

Detailed explanation

Let \(u\) be the initial vertical velocity of the body by which it is projected vertically upward. If \(t\) be the time taken by the body to reach a height \(h\) from the point of projection, then using equation of vertical motion,…
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