COMEDK · Physics · 4. Motion In Two Dimensions
A body is moving along a circular path of radius '\(r\)' with a frequency of revolution numerically equal to the radius of the circular path. What is the acceleration of the body if radius of the path is \(\left(\dfrac{5}{\pi}\right) m\) ?
- A \(500 \pi \mathrm{~ms}^{-2}\)
- B \(25 \pi \mathrm{~ms}^{-2}\)
- C \(100 \pi \mathrm{~ms}^{-2}\)
- D \(\left(\dfrac{500}{\pi}\right) \mathrm{ms}^{-2}\)
Answer & Solution
Correct Answer
(D) \(\left(\dfrac{500}{\pi}\right) \mathrm{ms}^{-2}\)
Step-by-step Solution
Detailed explanation
The acceleration of a body moving in a circular path is the centripetal acceleration, given by \(a = \omega^2 r\). The angular velocity \(\omega\) is related to the frequency \(f\) by the formula \(\omega = 2 \pi f\). Given that the frequency \(f\) is numerically equal to the…
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