COMEDK · Physics · 15. Oscillations
A body is executing SHM. When its displacements from the mean position are \(4 \mathrm{~cm}\) and \(5 \mathrm{~cm}\) it has velocity \(10 \mathrm{~cms}^{-1}\) and \(8 \mathrm{~cms}^{-1}\) respectively. Its periodic time \(\mathrm{t}\) is
- A 2\(\pi\) sec
- B \(\dfrac{3 \pi}{2} \mathrm{sec}\)
- C \(\dfrac{2 \pi}{3} \sec\)
- D \(\pi\) sec
Answer & Solution
Correct Answer
(D) \(\pi\) sec
Step-by-step Solution
Detailed explanation
The velocity \(v\) of a particle executing simple harmonic motion at a displacement \(x\) is given by \(v = \omega \sqrt{A^2 - x^2}\), where \(A\) is the amplitude and \(\omega\) is the angular frequency. For the first case,…
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