COMEDK · Physics · 5. Laws of Motion
A block slides on rough horizontal surface with a velocity of \(20 \mathrm{~m} / \mathrm{s}\). It comes to rest after travelling a distance of 80 m . The coefficient of kinetic friction between block and surface is (Take, \(\left.g=10 \mathrm{~m} / \mathrm{s}^2\right)\)
- A 0.2
- B 0.25
- C 0.125
- D 0.05
Answer & Solution
Correct Answer
(B) 0.25
Step-by-step Solution
Detailed explanation
Friction force, \(F=\mu N\) and acceleration, \(a=\frac{-F}{m}=-\frac{\mu m g}{m}\) \(a=-\mu g=-10 \mu\) Using third equation of motion,…
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