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COMEDK · Physics · 6. Work Power Energy

A block of mass 1.5 kg moves along the floor of a hall with a speed of \(5\ ms^{-1}\). It strikes an uncompressed spring and compresses it till the block becomes motionless. If the force constant of the spring is 10000 Nm\(^{-1}\) and the spring is compressed by 5cm, calculate the effective force of kinetic friction.

  1. A \(16.4\) N
  2. B \(0\)
  3. C \(18.7\) N
  4. D \(125\) N
Verified Solution

Answer & Solution

Correct Answer

(D) \(125\) N

Step-by-step Solution

Detailed explanation

Initial kinetic energy of the block is \(K_i = \dfrac{1}{2}mv^2\). Final kinetic energy of the block is \(K_f = 0\). Work done by the spring force is \(W_s = -\dfrac{1}{2}kx^2\). Work done by the kinetic friction is \(W_f = -f_k x\). Using the work-energy theorem,…
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