COMEDK · Physics · 12. Thermal Properties of Matter
A block of a certain material is heated to a temperature of 500° C and then placed on a large ice block. If 1.455 kg of ice melts, find the mass of the block. Specific heat of the material is \(0.39\ Jg^{-1}C^{-1}\) and heat of fusion of water is \(335\ Jg^{-1}\).
- A \(1.455\)kg
- B \(0.67\)kg
- C \(2.5\)kg
- D \(2.67\)kg
Answer & Solution
Correct Answer
(C) \(2.5\)kg
Step-by-step Solution
Detailed explanation
Let the mass of the block be \(m\) grams. Heat lost by the block in cooling from \(500^\circ\text{C}\) to \(0^\circ\text{C}\) is given by: \(Q_{\text{lost}} = m \times s \times \Delta T\) \(Q_{\text{lost}} = m \times 0.39 \times (500 - 0) = 195m \text{ J}\) Heat gained by the…
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