COMEDK · Physics · 26. Wave Optics
A beam of light of wavelength \(600 \mathrm{~nm}\) from a distant source falls on a single slit \(1 \mathrm{~mm}\) wide and the resulting diffraction pattern is observed on a screen \(2 \mathrm{~m}\) away. The distance between the first dark fringes on either side of the central bright fringe is
- A \(1.2 \mathrm{~mm}\)
- B \(1.2 \mathrm{~cm}\)
- C \(2.4 \mathrm{~cm}\)
- D \(2.4 \mathrm{~mm}\)
Answer & Solution
Correct Answer
(D) \(2.4 \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
Given, wavelength of light beam, \[ \begin{aligned} \lambda &=600 \mathrm{~nm} \\ &=600 \times 10^{-9} \mathrm{~m} \end{aligned} \] Distance between slits. \(d=1 \mathrm{~mm}=10^{-3} \mathrm{~m}\) Distance between slits and screen, \(D=2 \mathrm{~m}\) Distance between first dark…
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