COMEDK · Physics · 20. Magnetic Properties of Matter
A bar magnet of length 12 cm is placed such that its north pole points towards the geographic north. Two neutral points which are separated by 16 cm are obtained on the equatorial axis of the bar magnet. What is the pole strength of the bar magnet if the horizontal component of the earth's field is \(1.25 \times 10^{-5}\ T\)?
- A \(1.042\ \text{Am}\)
- B \(3.024\ \text{Am}\)
- C \(10.24\ \text{Am}\)
- D \(2.032\ \text{Am}\)
Answer & Solution
Correct Answer
(A) \(1.042\ \text{Am}\)
Step-by-step Solution
Detailed explanation
Length of the bar magnet, \(2l = 12\text{ cm} = 0.12\text{ m}\) \(l = 0.06\text{ m}\) The neutral points are obtained on the equatorial axis. The distance between the two neutral points is \(16\text{ cm}\). Distance of each neutral point from the centre of the magnet,…
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