COMEDK · Physics · 20. Magnetic Properties of Matter
A bar magnet is oscillating in the earth's magnetic field with a period \(T\). What happens to its period and motion, if its mass is quadrupled?
- A Motion remains simple harmonic with time period \(4 T\).
- B Motion remains simple harmonic with time period nearly constant.
- C Motion remains simple harmonic and time period becomes \(T / 2\)
- D Motion remains simple harmonic with time period \(2 T\).
Answer & Solution
Correct Answer
(D) Motion remains simple harmonic with time period \(2 T\).
Step-by-step Solution
Detailed explanation
The time period \(T\) of a bar magnet oscillating in a uniform magnetic field \(B\) is given by the formula \(T = 2\pi \sqrt{\dfrac{I}{MB}}\), where \(I\) is the moment of inertia of the magnet and \(M\) is its magnetic dipole moment. For a bar magnet of mass \(m\), length…
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