COMEDK · Physics · 20. Magnetic Properties of Matter
A bar magnet is oscillating in the earth's magnetic field with a period \(T\). When the length of the bar magnet is doubled and its mass is quadrupled (while its magnetic moment remains constant), the time period is \(T_1\). The ratio of \(T_1\) to \(T\) is:
- A \(1: 2\)
- B \(4: 1\)
- C \(2: 1\)
- D \(1: 4\)
Answer & Solution
Correct Answer
(B) \(4: 1\)
Step-by-step Solution
Detailed explanation
Time period: \(T = 2\pi\sqrt{\dfrac{I}{MB_H}}\), where \(I = \dfrac{ml^2}{12}\) is the moment of inertia. New moment of inertia with \(m' = 4m\) and \(l' = 2l\): \(I' = \dfrac{4m \cdot (2l)^2}{12} = \dfrac{4m \cdot 4l^2}{12} = 16\left(\dfrac{ml^2}{12}\right) = 16I\) Since…
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