COMEDK · Physics · 4. Motion In Two Dimensions
A ball is moving in a circular path of radius \(5 \mathrm{~m}\). If tangential acceleration at any instant is \(10 \mathrm{~ms}^{-2}\) and the net acceleration makes an angle of \(30^{\circ}\) with the centripetal acceleration, then, the instantaneous speed is
- A \(50 \sqrt{3} \mathrm{~ms}^{-1}\)
- B \(5.4 \mathrm{~ms}^{-1}\)
- C \(9.3 \mathrm{~ms}^{-1}\)
- D \(6.6 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(9.3 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
The tangential acceleration is given as \(a_t = 10 \mathrm{~ms}^{-2}\). The centripetal acceleration is given by \(a_c = \dfrac{v^2}{r}\), where \(v\) is the instantaneous speed and \(r = 5 \mathrm{~m}\). Thus, \(a_c = \dfrac{v^2}{5}\). The net acceleration \(\vec{a}\) is the…
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