COMEDK · Physics · 6. Work Power Energy
A ball falls under gravity from a height of 10m with an initial downward velocity \(u\). It loses three-fifths (or 60%) of its energy in collision and then rises back to 5m. The initial velocity \(u\) is (\(g = 10 \text{ ms}^{-2}\))
- A \(1\ ms^{-1}\)
- B \(10\ ms^{-1}\)
- C \(7.07\ ms^{-1}\)
- D \(0.707\ ms^{-1}\)
Answer & Solution
Correct Answer
(C) \(7.07\ ms^{-1}\)
Step-by-step Solution
Detailed explanation
Let the mass of the ball be \(m\) Initial total energy of the ball at height \(h_1 = 10\) is \(E_i = mgh_1 + \dfrac{1}{2}mu^2\) \(E_i = m(10)(10) + 0.5mu^2 = 100m + 0.5mu^2\) The ball loses \(60\%\) of its energy upon collision, so the remaining energy is \(0.4E_i\) The ball…
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