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COMEDK · Physics · 16. Waves and Sound

\(90 \mathrm{~dB}\) sound is \(x\) times more intense than \(40 \mathrm{~dB}\) sound, then \(x\) is

  1. A 5
  2. B 50
  3. C \(10^{5}\)
  4. D 500
Verified Solution

Answer & Solution

Correct Answer

(C) \(10^{5}\)

Step-by-step Solution

Detailed explanation

The level of sound is given by \(L=10 \log \left(\frac{I}{I_{0}}\right) \mathrm{dB}\) Let for \(40 \mathrm{~dB}\) sound intensity be \(I\) and for \(90 \mathrm{~dB}\) sound intensity be \(I_{x}\), then \(40=10 \log \left(\frac{I}{I_{0}}\right)\)…