COMEDK · Physics · 17. Electrostatics
3 point charges each of \(-\mathrm{q}\) are placed on the circumference of a circle of diameter \(2 \mathrm{a}\) at \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) respectively as shown in figure. The electric field at \(\mathrm{O}\) is
- A \(\dfrac{\mathrm{Kq}}{\mathrm{a}}\) towards \(\mathrm{OA}\)
- B \(\dfrac{\mathrm{Kq}}{2 \mathrm{a}}\) towards \(\mathrm{OC}\)
- C \(\dfrac{\mathrm{Kq}}{\mathrm{a}}\) towards \(\mathrm{OB}\)
- D Zero
Answer & Solution
Correct Answer
(C) \(\dfrac{\mathrm{Kq}}{\mathrm{a}}\) towards \(\mathrm{OB}\)
Step-by-step Solution
Detailed explanation
The charges are placed at points A, B, and C on the circumference of a circle with center O and radius \(a\). The charges are \(q_A = -q\), \(q_B = -q\), and \(q_C = -q\). The electric field at the center O due to a point charge \(q\) at distance \(a\) is given by…
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