ExamBro
ExamBro
COMEDK · Physics · 12. Thermal Properties of Matter

100 g of ice at \(0^{\circ} \mathrm{C}\) is mixed with 100 g of water at \(80^{\circ} \mathrm{C}\). The final temperature of the mixture is (Given, latent heat of fusion of ice, \(L_f=80 \mathrm{cal} / \mathrm{g}\) and specific heat capacity of water, \(S_{\text {water }}=1 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C}\) )

  1. A \(0^{\circ} \mathrm{C}\)
  2. B \(20^{\circ} \mathrm{C}\)
  3. C \(40^{\circ} \mathrm{C}\)
  4. D \(60^{\circ} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0^{\circ} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Let the final temperature of mixture be \(T^{\circ} \mathrm{C}\). From principle of calorimetry, Heat given by 100 g of water \(=\) Heat taken by 100 g of ice \(m_1 S_{\text {water }}\left(\Delta T_1\right)=m_2 L_f+m_2 S_{\text {water }} \Delta T_2\) Substituting the given…