COMEDK · Physics · 13. Thermodynamics
1 kg of water at \(100^\circ\)C is converted to steam at the same temperature. Volume of 1 cc of water changes to \(1671 \times 10^3\) cc on boiling. The change in internal energy of the system is (Latent Heat of vaporisation of water is \(22.68 \times 10^5\ J\ kg^{-1}\); 1 atm \(= 1.0 \times 10^5\) Pa)
- A \(19.01 \times 10^5\ J\)
- B \(20.1 \times 10^5\ J\)
- C \(21.01 \times 10^5\ J\)
- D \(21.01 \times 10^3\ J\)
Answer & Solution
Correct Answer
(C) \(21.01 \times 10^5\ J\)
Step-by-step Solution
Detailed explanation
Given the final volume of 1 kg of steam is \(1671 \times 10^3\) cc \(= 1.671\) m\(^3\). Initial volume of 1 kg of water is \(1000\) cc \(= 10^{-3}\) m\(^3\). Change in volume, \(\Delta V = 1.671 - 0.001 = 1.670\) m\(^3\). Work done,…
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