COMEDK · Maths · 28. Indefinite Integration
\(\int \frac{\left(x^{3}+3 x^{2}+3 x+1\right)}{(x+1)^{5}} d x=\)
- A \(\tan ^{-1} x+c\)
- B \(\log (x+1)+c\)
- C \(\frac{1}{5} \log (x+1)+c\)
- D \(-\frac{1}{(x+1)}+c\)
Answer & Solution
Correct Answer
(D) \(-\frac{1}{(x+1)}+c\)
Step-by-step Solution
Detailed explanation
\(\int \frac{x^{3}+3 x^{2}+3 x+1}{(x+1)^{5}} d x\) \(\begin{aligned} &=\int \frac{(x+1)^{3}}{(x+1)^{5}} d x=\int \frac{d x}{(x+1)^{2}} \\ &=-\frac{1}{x+1}+c \end{aligned}\)
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