COMEDK · Maths · 28. Indefinite Integration
\(\displaystyle\int \dfrac{x + 1}{x(1 + x e^x)} dx =\)
- A \(\log\left|\dfrac{c(1 + x e^x)}{x e^x}\right|\)
- B \(\log\left|\dfrac{c x e^x}{1 + x e^x}\right|\)
- C \(\log\left|\dfrac{c}{x e^x(1 + x e^x)}\right|\)
- D \(\log|c x e^x(1 + x e^x)|\)
Answer & Solution
Correct Answer
(B) \(\log\left|\dfrac{c x e^x}{1 + x e^x}\right|\)
Step-by-step Solution
Detailed explanation
Let \(I = \displaystyle\int \dfrac{x + 1}{x(1 + x e^x)} dx\) Multiplying the numerator and the denominator by \(e^x\): \(I = \displaystyle\int \dfrac{(x + 1)e^x}{x e^x(1 + x e^x)} dx\) Let \(x e^x = t\). Differentiating both sides with respect to \(x\):…
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