COMEDK · Maths · 16. Limits
\(\lim _{x \rightarrow \infty}\left(1-\frac{4}{x-1}\right)^{3 x-1}\) is equal to
- A \(e^{12}\)
- B \(e^{-12}\)
- C \(e^{4}\)
- D \(e^{3}\)
Answer & Solution
Correct Answer
(B) \(e^{-12}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \lim _{x \rightarrow \infty}(1-&\left.\frac{4}{x-1}\right)^{3 x-1} \\ &=e^{\lim _{x \rightarrow \infty}}\left(\frac{-4}{x-1}\right)\left(1^{\infty} \text { form] }\right.\\ &=e^{\lim _{x \rightarrow \infty}-\frac{12 x+4}{x-1}}=e^{-12} \end{aligned}\)
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