COMEDK · Maths · 16. Limits
\(\lim _\limits{x \rightarrow 0}\left(\dfrac{\sin a x}{\sin b x}\right)^k \text { equals }\)
- A \(\dfrac{b}{a}\)
- B \(\left(\dfrac{b}{a}\right)^k\)
- C \(\left(\dfrac{a}{b}\right)^k\)
- D \(\dfrac{a}{b}\)
Answer & Solution
Correct Answer
(C) \(\left(\dfrac{a}{b}\right)^k\)
Step-by-step Solution
Detailed explanation
The given limit is \(L = \lim_{x \rightarrow 0} \left( \dfrac{\sin ax}{\sin bx} \right)^k\). We can rewrite the expression inside the limit as: \(\dfrac{\sin ax}{\sin bx} = \dfrac{\sin ax}{ax} \cdot \dfrac{bx}{\sin bx} \cdot \dfrac{ax}{bx}\) Using the standard limit…
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