COMEDK · Maths · 6. Mathematical Induction
Using mathematical induction, the numbers \(a_n s\) are defined by \(a_0=1, a_{n+1}=3 n^2+n+a_n\), \((n \geq 0)\). Then, \(a_n\) is equal to
- A \(n^3+n^2+1\)
- B \(n^3-n^2+1\)
- C \(n^3-n^2\)
- D \(n^3+n^2\)
Answer & Solution
Correct Answer
(B) \(n^3-n^2+1\)
Step-by-step Solution
Detailed explanation
Given, \(a_0=1, a_{n+1}=3 n^2+n+a_n\) \(\begin{array}{ll} \Rightarrow & a_1=3(0)^2+(0)+a_0=0+0+1=1 \\ \Rightarrow & a_2=3(1)^2+(1) a_1=3+1+1=5 \end{array}\) From option (b), Let \(P(n)=n^3-n^2+1\)…
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