COMEDK · Maths · 33. Vector Algebra
Unit vector perpendicular to \(\hat{\mathbf{i}}-2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) and lying in the plane containing \(\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}\) and \(-\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+\hat{\mathbf{k}}\) is
- A \(8 \hat{\mathbf{i}}-7 \hat{\mathbf{j}}+11 \hat{\mathbf{k}}\)
- B \(8 \hat{\mathbf{i}}+7 \hat{\mathbf{j}}-11 \hat{\mathbf{k}}\)
- C \(8 \hat{\mathbf{i}}-7 \hat{\mathbf{j}}-11 \hat{\mathbf{k}}\)
- D \(\frac{1}{\sqrt{234}}(8 \hat{\mathbf{i}}-7 \hat{\mathbf{j}}-11 \hat{\mathbf{k}})\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{\sqrt{234}}(8 \hat{\mathbf{i}}-7 \hat{\mathbf{j}}-11 \hat{\mathbf{k}})\)
Step-by-step Solution
Detailed explanation
Let \(\mathbf{a}=\hat{\mathbf{i}}-2 \hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}\) and \(\mathbf{c}=-\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+\hat{\mathbf{k}}\) Now,…
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