COMEDK · Maths · 36. Probability
Three vertices are chosen randomly from the nine vertices of a regular 9 -sided polygon. The probability that they form the vertices of an isosceles triangle, is
- A \(\frac{4}{7}\)
- B \(\frac{3}{7}\)
- C \(\frac{2}{7}\)
- D \(\frac{5}{7}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{7}\)
Step-by-step Solution
Detailed explanation
Number of triangles formed \(={ }^9 C_3\) Number of isosceles triangles \(=9 \times\left(\frac{9-1}{2}\right)\) \(=9 \times 4=36\) So, required probability…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- \(\int \sqrt{2ax - x^2}\ dx =\)COMEDK 2026 Medium
- If \((\vec{a} + \vec{b}) \perp \vec{b}\) and \((\vec{a} + 2\vec{b}) \perp \vec{a}\), thenCOMEDK 2026 Medium
- The second derivative of \(\sin 3x \cos 5x\) is:COMEDK 2026 Medium
- If \(f(x)=\dfrac{(x+1)^7 \sqrt{1+x^2}}{\left(x^2-x+1\right)^6}\) then the value of \(f^{\prime}(0)\) is equal toCOMEDK 2023 Medium
- The interval \(I\) such that \(\int_{0}^{1} \frac{d x}{\sqrt{1+x^{4}}} \in I\) is given byCOMEDK 2018 Medium
- If \(3 x \equiv 5(\bmod 7)\), thenCOMEDK 2018 Easy
More PYQs from COMEDK
- The total energy stored in the condenser system shown in the figure will be
COMEDK 2018 Easy - A given chemical reaction is represented by the following stoichiometric equation.
\(3 X+2 Y+\dfrac{5}{2} Z \rightarrow P_1+P_2+P_3\)
The rate of reaction can be expressed as _________.COMEDK 2024 Medium - The sum of all 4-digit numbers that can be formed by using the digits \(2,4,6,8\) (repetition of digits is not allowed) isCOMEDK 2017 Hard
- If \(C\) be the capacitance and \(V\) be the electric potential, then the dimensional formula of \(\mathrm{CV}^2\) isCOMEDK 2023 Easy
- The value of the expression \(\cos^{-1}\left(\cos\dfrac{7\pi}{6}\right) + \sin^{-1}\left(\sin\dfrac{22\pi}{3}\right) + \tan^{-1}\left(\tan\dfrac{4\pi}{5}\right)\) is:COMEDK 2026 Medium
- \(S \equiv x^2+y^2+2 x+3 y+1=0\) and
\(S^{\prime} \equiv x^2+y^2+4 x+3 y+2=0\) are two circles.
The point \((-3,-2)\) liesCOMEDK 2022 Easy