COMEDK · Maths · 16. Limits
The value of \(\lim _{x \rightarrow \infty}\left(\frac{x^2-2 x+1}{x^2-4 x+2}\right)^{2 x}\) is
- A \(e^2\)
- B \(e^4\)
- C \(e\)
- D \(e^{16}\)
Answer & Solution
Correct Answer
(B) \(e^4\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Let } L=\lim _{x \rightarrow \infty}\left(\frac{x^2-2 x+1}{x^2-4 x+2}\right)^{2 x} \\ & \Rightarrow \ln L=\lim _{x \rightarrow \infty}\left[2 x \ln \left(\frac{x^2-2 x+1}{x^2-4 x+2}\right)\right] \\ & \Rightarrow \ln L=\lim _{x \rightarrow…
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