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COMEDK · Maths · 28. Indefinite Integration

The value of \(\int \frac{x^{2}+1}{x^{2}-1} d x\) is

  1. A \(\log \left(\frac{x+1}{x-1}\right)+C\)
  2. B \(\log \left(\frac{x-1}{x+1}\right)+C\)
  3. C \(\log \left(x^{2}-1\right)+C\)
  4. D \(x+\log \left(\frac{x-1}{x+1}\right)+C\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x+\log \left(\frac{x-1}{x+1}\right)+C\)

Step-by-step Solution

Detailed explanation

Let \(I=\int \frac{x^{2}+1}{x^{2}-1} d x=\int \frac{x^{2}-1+2}{x^{2}-1} d x\) \[ =\int\left(1+\frac{2}{x^{2}-1}\right) d x=x+2 \times \frac{1}{2} \log \left|\frac{x-1}{x+1}\right|+C \] \[ =x+\log \left|\frac{x-1}{x+1}\right|+C \]