COMEDK · Maths · 28. Indefinite Integration
The value of \(\int \frac{x^{2}+1}{x^{2}-1} d x\) is
- A \(\log \left(\frac{x+1}{x-1}\right)+C\)
- B \(\log \left(\frac{x-1}{x+1}\right)+C\)
- C \(\log \left(x^{2}-1\right)+C\)
- D \(x+\log \left(\frac{x-1}{x+1}\right)+C\)
Answer & Solution
Correct Answer
(D) \(x+\log \left(\frac{x-1}{x+1}\right)+C\)
Step-by-step Solution
Detailed explanation
Let \(I=\int \frac{x^{2}+1}{x^{2}-1} d x=\int \frac{x^{2}-1+2}{x^{2}-1} d x\) \[ =\int\left(1+\frac{2}{x^{2}-1}\right) d x=x+2 \times \frac{1}{2} \log \left|\frac{x-1}{x+1}\right|+C \] \[ =x+\log \left|\frac{x-1}{x+1}\right|+C \]
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