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COMEDK · Maths · 16. Limits

The value of \(\lim _{x \rightarrow 0} \frac{e^{a x}-e^{b x}}{2 x}\) is equal to

  1. A \(\frac{a+b}{2}\)
  2. B \(\frac{a-b}{2}\)
  3. C \(\frac{e^{a b}}{2}\)
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{a-b}{2}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \lim _{x \rightarrow 0} \frac{e^{a x}-e^{b x}}{2 x} \\ & =\lim _{x \rightarrow 0} \frac{\left(1+a x+\frac{(a x)^2}{2 !}+\frac{(a x)^3}{3 !}+\ldots\right)}{-\left(1+b x+\frac{(b x)^2}{2 !}+\frac{(b x)^3}{3 !}\right)} \\ & =\lim _{x \rightarrow 0}…