COMEDK · Maths · 16. Limits
The value of \(\lim _{x \rightarrow 0} \frac{\sin 3 x+e^{2 x}-1}{x}\) is equal to
- A 2
- B 3
- C 5
- D 1
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0} \frac{\sin 3 x+e^{2 x}-1}{x}\) Put \(x=0 \Rightarrow \frac{\sin 0+e^0-1}{0}\left(\frac{0}{0}\right)\) Using L'hospital's rule we can differentiate both Numerator and denominator separately…
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