COMEDK · Maths · 22. Determinants
The value of \(\left|\begin{array}{ccc}1 & 1 & 1 \\ b c & c a & a b \\ b+c & c+a & a+b\end{array}\right|\) is
- A \(1\)
- B \(0\)
- C \((a-b)(b-c)(c-a)\)
- D \((a+b)(b+c)(c+a)\)
Answer & Solution
Correct Answer
(C) \((a-b)(b-c)(c-a)\)
Step-by-step Solution
Detailed explanation
We have, \(\left|\begin{array}{ccc}1 & 1 & 1 \\ b c & c a & a b \\ b+c & c+a & a+b\end{array}\right|\) On applying \(C_{1} \rightarrow C_{1}-C_{2}, C_{2} \rightarrow C_{2}-C_{3}\), we get…
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