COMEDK · Maths · 8. Trigonometric Ratios & Identities
The value of \(\sin 18^{\circ}+\cos 36^{\circ}\) is equal to
- A \(\sqrt{5}\)
- B \(\frac{\sqrt{5}}{2}\)
- C \(2 \sqrt{5}\)
- D \(\frac{\sqrt{5}-1}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{\sqrt{5}}{2}\)
Step-by-step Solution
Detailed explanation
We have, \(\sin 18^{\circ}+\cos 36^{\circ}\)…
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