COMEDK · Maths · 23. Inverse Trigonometric Functions
The value of \(\sin \left[\cot ^{-}\left\{\cos \left(\tan ^{-1} x\right)\right\}\right]\) is
- A \(\left(\sqrt{\frac{1+x^{2}}{2+x^{2}}}\right)\)
- B \(\left(\sqrt{\frac{2+x^{2}}{1+x^{2}}}\right)\)
- C \(\left(\sqrt{\frac{x^{2}-2}{x^{2}-1}}\right)\)
- D \(\left(\sqrt{\frac{x^{2}-1}{x^{2}-2}}\right)\)
Answer & Solution
Correct Answer
(A) \(\left(\sqrt{\frac{1+x^{2}}{2+x^{2}}}\right)\)
Step-by-step Solution
Detailed explanation
We have \(\sin \left[\cot ^{-1}\left\{\cos \left(\tan ^{-1} x\right)\right\}\right]\) Now, \(\cos \left(\tan ^{-1} x\right)=\cos \left[\cos ^{-1} \frac{1}{\sqrt{x^{2}+1}}\right]\) \(=\frac{1}{\sqrt{x^{2}+1}}\)…
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