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COMEDK · Maths · 3. Complex Number

The value of \((-\sqrt{-1})^{4 n-3}\), where \(n \in N\), set of natural numbers is

  1. A 1
  2. B -1
  3. C -i
  4. D i
Verified Solution

Answer & Solution

Correct Answer

(C) -i

Step-by-step Solution

Detailed explanation

Given the expression \((-\sqrt{-1})^{4n-3}\), where \(n \in N\). Since \(\sqrt{-1} = i\), the expression becomes \((-i)^{4n-3}\). This can be written as \((-1)^{4n-3} \times i^{4n-3}\). Since \(4n-3\) is an odd number for any \(n \in N\), \((-1)^{4n-3} = -1\). Now,…