COMEDK · Maths · 3. Complex Number
The value of \((-\sqrt{-1})^{4 n-3}\), where \(n \in N\), set of natural numbers is
- A 1
- B -1
- C -i
- D i
Answer & Solution
Correct Answer
(C) -i
Step-by-step Solution
Detailed explanation
Given the expression \((-\sqrt{-1})^{4n-3}\), where \(n \in N\). Since \(\sqrt{-1} = i\), the expression becomes \((-i)^{4n-3}\). This can be written as \((-1)^{4n-3} \times i^{4n-3}\). Since \(4n-3\) is an odd number for any \(n \in N\), \((-1)^{4n-3} = -1\). Now,…
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