COMEDK · Maths · 23. Inverse Trigonometric Functions
The value of \(\tan \left\{\cos ^{-1}\left(\dfrac{\sqrt{2}}{2}\right)-\dfrac{\pi}{2}\right\}\) is
- A \(1\)
- B \(\dfrac{1}{\sqrt{2}}\)
- C \(-\dfrac{1}{\sqrt{2}}\)
- D \(-1\)
Answer & Solution
Correct Answer
(D) \(-1\)
Step-by-step Solution
Detailed explanation
The given expression is \(\tan \left\{\cos ^{-1}\left(\dfrac{\sqrt{2}}{2}\right)-\dfrac{\pi}{2}\right\}\). First, simplify the term inside the cosine inverse function: \(\dfrac{\sqrt{2}}{2} = \dfrac{1}{\sqrt{2}}\). We know that…
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