COMEDK · Maths · 5. Sequences and Series
The value of \(1 \cdot 1 !+2 \cdot 2 !+3 \cdot 3 !+\quad+n \cdot n !\) is
- A \((n+1) !\)
- B \((n+1) !+1\)
- C \((n+1) !-1\)
- D None of these
Answer & Solution
Correct Answer
(C) \((n+1) !-1\)
Step-by-step Solution
Detailed explanation
The general term of the series is \(T_r = r \cdot r!\). We can rewrite the general term as \(T_r = (r+1-1) \cdot r! = (r+1) \cdot r! - r!\). Since \((r+1) \cdot r! = (r+1)!\), we have \(T_r = (r+1)! - r!\). The sum \(S_n = \sum_{r=1}^{n} T_r = \sum_{r=1}^{n} ((r+1)! - r!)\).…
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