COMEDK · Maths · 33. Vector Algebra
The unit vector in the direction of the vector \(\mathbf{a}+2 \mathbf{b}-\mathbf{c}\) is equal to
- A \(\frac{\mathbf{a}+2 \mathbf{b}-\mathbf{c}}{\sqrt{6}}\)
- B \(\frac{\mathbf{a}+2 \mathbf{b}-\mathbf{c}}{2}\)
- C \(\frac{\mathbf{a}+2 \mathbf{b}-\mathbf{c}}{4}\)
- D \(\frac{\mathbf{a}+2 \mathbf{b}-\mathbf{c}}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathbf{a}+2 \mathbf{b}-\mathbf{c}}{\sqrt{6}}\)
Step-by-step Solution
Detailed explanation
Given that, \(+2 b-c\) So, required unit vector \(=\frac{a+2 b-c}{\sqrt{1+4+1}}=\frac{a+2 b-\mathbb{c}}{\sqrt{6}}\)
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