COMEDK · Maths · 5. Sequences and Series
The sum of the series
\(\frac{1^{2}}{1 \cdot 2}+\frac{1^{2}+2^{2}}{2 \cdot 3}+\frac{1^{2}+2^{2}+3^{2}}{3 \cdot 4}+\ldots\) upto 20 terms is
- A \(\frac{205}{3}\)
- B \(\frac{200}{3}\)
- C \(\frac{220}{3}\)
- D \(\frac{210}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{220}{3}\)
Step-by-step Solution
Detailed explanation
Let \[ S=\frac{1^{2}}{1 \cdot 2}+\frac{1^{2}+2^{2}}{2 \cdot 3}+\frac{1^{2}+2^{2}+3^{2}}{3 \cdot 4}+\ldots . \] upto 20 terms Let \(t_{n}\) be \(n\)th terms of series. Then, \(t_{n}=\frac{1^{2}+2^{2}+3^{2}+\ldots+n^{2}}{n \cdot(n+1)}\)…
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