COMEDK · Maths · 27. Application of Derivatives
The slope of the tangent to the curve, \(y=x^3-3 x^2 y\) at \((1,1)\) is
- A \(\frac{1}{3}\)
- B -3
- C \(\frac{-1}{3}\)
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
We have, \(y=x^3-3 x^2 y\)....(i) Differentiate Eq. (i) w.r.t. \(x\) \(\begin{aligned} \therefore \quad \frac{d y}{d x} & =3 x^2-3\left(2 x y-x^2 \frac{d y}{d x}\right) \\ \frac{d y}{d x} & =3 x^2-6 x y+3 x^2 \frac{d y}{d x} \end{aligned}\)…
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