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COMEDK · Maths · 8. Trigonometric Ratios & Identities

The sides \(a, b, c\) of a triangle are in AP. If \(\cos \alpha=\frac{a}{b+c}, \cos \beta=\frac{b}{c+a}, \cos \gamma=\frac{c}{a+b}\) then \(\tan ^{2} \frac{\alpha}{2}+\tan ^{2} \frac{\gamma}{2}=\)

  1. A 1
  2. B \(\frac{1}{2}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{2}{3}\)

Step-by-step Solution

Detailed explanation

\(\frac{\cos \alpha}{1}=\frac{a}{b+c} \Rightarrow \frac{1}{\cos \alpha}=\frac{b+c}{a}\) By componendo and dividendo,we have \(\frac{1-\cos \alpha}{1+\cos \alpha}=\frac{b+c-a}{b+c+a}\)…