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COMEDK · Maths · 7. Binomial Theorem

The ratio of the coefficient of \(x^3\) to the term independent of \(x\) in the expansion of \(\left(2 x+\dfrac{1}{x^2}\right)^{12}\) is

  1. A \(8: 1\)
  2. B \(9: 1\)
  3. C \(9: 8\)
  4. D \(8: 9\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(8: 9\)

Step-by-step Solution

Detailed explanation

The general term in the expansion of \(\left(2x + \dfrac{1}{x^2}\right)^{12}\) is given by \(T_{r+1} = ^{12}C_{r} (2x)^{12-r} \left(\dfrac{1}{x^2}\right)^{r} = ^{12}C_{r} 2^{12-r} x^{12-r} x^{-2r} = ^{12}C_{r} 2^{12-r} x^{12-3r}\). To find the coefficient of \(x^3\), set the…