COMEDK · Maths · 12. Circle
The radius of the circle passing through the point \((6,2)\) and two of whose diameters are \(x+y=6\) and \(x+2 y=4\) is
- A \(4\)
- B \(6\)
- C \(20\)
- D \(\sqrt{20}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{20}\)
Step-by-step Solution
Detailed explanation
We have, diameters of circle are \[ x+y=6 \text { and } x+2 y=4 \] On solving above equations, we get \[ x=8 \text { and } y=-2 \] \(\therefore\) Centre of circle is \((8,-2)\). Since, circle passes through \((6,2)\).…
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