COMEDK · Maths · 12. Circle
The radius and centre of circle which equation is \(3 x^2+3 y^2+6 x+12 y+5=0\) is
- A \((-3,-4), \sqrt{20}\)
- B \((3,4), \sqrt{20}\)
- C \((-1,-2), 5 \sqrt{\frac{2}{3}}\)
- D \((1,2), 5 \sqrt{\frac{2}{3}}\)
Answer & Solution
Correct Answer
(C) \((-1,-2), 5 \sqrt{\frac{2}{3}}\)
Step-by-step Solution
Detailed explanation
If equation of circle is \(x^2+y^2+2 g x+2 f g+c=0\) Then, centre \(=(-g,-f)\) \(\begin{aligned} & \text { Radius }=\sqrt{g^2+f^2-c} \\ & \Rightarrow x^2+y^2+2 x+4 y+\frac{5}{3}=0 \end{aligned}\)…
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