COMEDK · Maths · 27. Application of Derivatives
The point on the circle \(x^{2}+y^{2}=2\) at the abscissa and ordinate increase at the same ate is
- A \((-1,-1)\)
- B \((1,-1)\)
- C \((1,1)\)
- D \((-1,4)\)
Answer & Solution
Correct Answer
(B) \((1,-1)\)
Step-by-step Solution
Detailed explanation
Given, equation of circle is \[ x^{2}+y^{2}=2 \quad \text{...(i)} \] Taking derivative w.r.t. ' \(t\) ' on both sides. \[ 2 x \frac{d x}{d t}+2 y \frac{d y}{d t}=0 \Rightarrow x \frac{d x}{d t}+y \frac{d y}{d t}=0 \] If abscissa and ordinate increase at the same rate, we have…
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