COMEDK · Maths · 34. Three Dimensional Geometry
The point of intersection of the lines \(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\) and \(\dfrac{x-4}{5}=\dfrac{y-1}{2}=z\) is
- A \((0,0,0)\)
- B \((1,1,1)\)
- C \((-1,-1,-1)\)
- D \((1,2,3)\)
Answer & Solution
Correct Answer
(C) \((-1,-1,-1)\)
Step-by-step Solution
Detailed explanation
Let the first line be \(\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{4} = s\). Then the coordinates of any point on this line are \((2s+1, 3s+2, 4s+3)\). Let the second line be \(\dfrac{x-4}{5} = \dfrac{y-1}{2} = \dfrac{z}{1} = t\). Then the coordinates of any point on this…
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