COMEDK · Maths · 34. Three Dimensional Geometry
The point of intersection of the lines \(\dfrac{x-1}{1}=\dfrac{y-1}{2}=\dfrac{z-2}{3}\) and \(\dfrac{x-5}{2}=\dfrac{y-2}{1}=z\) is
- A \((1,-2,0)\)
- B \((3,1,0)\)
- C \((-2,-5,-7)\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
Let the first line be \(\dfrac{x-1}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3} = \lambda\). Then any point on the first line is \((1+\lambda, 1+2\lambda, 2+3\lambda)\). Let the second line be \(\dfrac{x-5}{2} = \dfrac{y-2}{1} = \dfrac{z}{1} = \mu\). Then any point on the second line…
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