COMEDK · Maths · 28. Indefinite Integration
The particular solution of \(\frac{y}{x} \frac{d y}{d x}=\frac{1+y^{2}}{1+x^{2}}\), when \(x=1, y=2\) is
- A \(5\left(1+y^{2}\right)=2\left(1+x^{2}\right)\)
- B \(2\left(1+y^{2}\right)=5\left(1+x^{2}\right)\)
- C \(5\left(1+y^{2}\right)=\left(1+x^{2}\right)\)
- D \(\left(1+y^{2}\right)=2\left(1+x^{2}\right)\)
Answer & Solution
Correct Answer
(B) \(2\left(1+y^{2}\right)=5\left(1+x^{2}\right)\)
Step-by-step Solution
Detailed explanation
We have, \(\quad \frac{y}{x} \frac{d y}{d x}=\frac{1+y^{2}}{1+x^{2}}\) \[ \begin{aligned} &\frac{y d y}{1+y^{2}}=\frac{x d x}{1+x^{2}} \\ &\frac{2 y d y}{1+y^{2}}=\frac{2 x d x}{1+x^{2}} \end{aligned} \] Integrating both sides, we get…
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