COMEDK · Maths · 32. Differential Equations
The particular solution of the differential equation \((x - y)(dx + dy) = (dx - dy)\) when \(y = -1\) and \(x = 0\) is
- A \(\log\left|\dfrac{x - y}{x + y}\right| = 1\)
- B \(\log|x - y| = x - y + 1\)
- C \(\log|x + y| = x - y + 1\)
- D \(\log|x - y| = x + y + 1\)
Answer & Solution
Correct Answer
(D) \(\log|x - y| = x + y + 1\)
Step-by-step Solution
Detailed explanation
Given differential equation is \((x - y)(dx + dy) = dx - dy\) Let \(x - y = u\) and \(x + y = w\) Differentiating, we get \(dx - dy = du\) and \(dx + dy = dw\) Substituting these in the given equation: \(u dw = du\) \(\dfrac{du}{u} = dw\) Integrating both sides:…
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