COMEDK · Maths · 32. Differential Equations
The particular solution of the differential equation \(\cos x \dfrac{d y}{d x}+y=\sin x\) at \(y(0)=1\)
- A \(y(\sec x+\tan x)=\sec x+\tan x-x+1\)
- B \(y(\sec x+\tan x)=\sec x+\tan x-x+2\)
- C \(y(\sec x+\tan x)=\sec x+\tan x-x\)
- D \(y(\sec x+\tan x)=\sec x+\tan x+x\)
Answer & Solution
Correct Answer
(C) \(y(\sec x+\tan x)=\sec x+\tan x-x\)
Step-by-step Solution
Detailed explanation
The given differential equation is \(\cos x \dfrac{dy}{dx} + y = \sin x\). Dividing by \(\cos x\), we get \(\dfrac{dy}{dx} + y \sec x = \tan x\). This is a linear differential equation of the form \(\dfrac{dy}{dx} + Py = Q\), where \(P = \sec x\) and \(Q = \tan x\). The…
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