COMEDK · Maths · 8. Trigonometric Ratios & Identities
The number of solutions of the equation \(|\cot x|=\cot x+\frac{1}{\sin x},(0 \leq x \leq 2 \pi)\) is
- A 0
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
With the help of group of cot \(x\), we know that When \(x \in\left(0, \frac{\pi}{2}\right] \cup\left(\pi, \frac{3 \pi}{2}\right]\), then \(\cot x \geq 0\) \(\therefore \quad|\cot x|=\cot x+\frac{1}{\sin x}\)…
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