COMEDK · Maths · 12. Circle
The number of common tangents to the circles \(x^{2}+y^{2}=4\) and \(x^{2}+y^{2}-6 x-8 y-24=0\) is,
- A 4
- B 3
- C 1
- D 2
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
We have, Equation of circle is \(x^{2}+y^{2}=4\). Its centre is \(C_{1}(0,0)\) and radius \(\left(r_{1}\right)\) is 2 . Equation of another circle is \[ x^{2}+y^{2}-6 x-8 y-24=0 \] i.e. \((x-3)^{2}+(y-4)^{2}=\langle 7)^{2}\). Its centre is \(C 2(3,4)\) and radius…
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