COMEDK · Maths · 3. Complex Number
\(\text { The modulus of the following complex number } \dfrac{1+i}{1-i}-\dfrac{1-i}{1+i} \text { is }\)
- A 2
- B 1
- C 16
- D 0
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
Let \(z = \dfrac{1+i}{1-i} - \dfrac{1-i}{1+i}\). Simplify the first term by multiplying the numerator and denominator by the conjugate of the denominator \((1+i)\):…
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